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0.75x^2-13x-56=0
a = 0.75; b = -13; c = -56;
Δ = b2-4ac
Δ = -132-4·0.75·(-56)
Δ = 337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{337}}{2*0.75}=\frac{13-\sqrt{337}}{1.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{337}}{2*0.75}=\frac{13+\sqrt{337}}{1.5} $
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